1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$9045 \times 39$$

Evaluate

$352755$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}9045\\\underline{\times\phantom{9999}39}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 9045 with 9. Write the result 81405 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}9045\\\underline{\times\phantom{9999}39}\\\phantom{\times9}81405\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 9045 with 3. Write the result 27135 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}9045\\\underline{\times\phantom{9999}39}\\\phantom{\times9}81405\\\underline{\phantom{\times}27135\phantom{9}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}9045\\\underline{\times\phantom{9999}39}\\\phantom{\times9}81405\\\underline{\phantom{\times}27135\phantom{9}}\\\phantom{\times}352755\end{array}$$

Show Solution

Factor

$3^{4}\times 5\times 13\times 67$