How to solve (a) 9309/29

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (a) 9309/29 | Equatix

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Question

$$9309 \div 29$$

Evaluate

$321$

Steps For Long Division Method

Use the $1^{st}$ digit $9$ from dividend $9309$

$$\begin{array}{l}\phantom{29)}\phantom{1}\\29\overline{)9309}\\\end{array}$$

Since $9$ is less than $29$, use the next digit $3$ from dividend $9309$ and add $0$ to the quotient

$$\begin{array}{l}\phantom{29)}0\phantom{2}\\29\overline{)9309}\\\end{array}$$

Use the $2^{nd}$ digit $3$ from dividend $9309$

$$\begin{array}{l}\phantom{29)}0\phantom{3}\\29\overline{)9309}\\\end{array}$$

Find closest multiple of $29$ to $93$. We see that $3 \times 29 = 87$ is the nearest. Now subtract $87$ from $93$ to get reminder $6$. Add $3$ to quotient.

$$\begin{array}{l}\phantom{29)}03\phantom{4}\\29\overline{)9309}\\\phantom{29)}\underline{\phantom{}87\phantom{99}}\\\phantom{29)9}6\\\end{array}$$

Use the $3^{rd}$ digit $0$ from dividend $9309$

$$\begin{array}{l}\phantom{29)}03\phantom{5}\\29\overline{)9309}\\\phantom{29)}\underline{\phantom{}87\phantom{99}}\\\phantom{29)9}60\\\end{array}$$

Find closest multiple of $29$ to $60$. We see that $2 \times 29 = 58$ is the nearest. Now subtract $58$ from $60$ to get reminder $2$. Add $2$ to quotient.

$$\begin{array}{l}\phantom{29)}032\phantom{6}\\29\overline{)9309}\\\phantom{29)}\underline{\phantom{}87\phantom{99}}\\\phantom{29)9}60\\\phantom{29)}\underline{\phantom{9}58\phantom{9}}\\\phantom{29)99}2\\\end{array}$$

Use the $4^{th}$ digit $9$ from dividend $9309$

$$\begin{array}{l}\phantom{29)}032\phantom{7}\\29\overline{)9309}\\\phantom{29)}\underline{\phantom{}87\phantom{99}}\\\phantom{29)9}60\\\phantom{29)}\underline{\phantom{9}58\phantom{9}}\\\phantom{29)99}29\\\end{array}$$

Find closest multiple of $29$ to $29$. We see that $1 \times 29 = 29$ is the nearest. Now subtract $29$ from $29$ to get reminder $0$. Add $1$ to quotient.

$$\begin{array}{l}\phantom{29)}0321\phantom{8}\\29\overline{)9309}\\\phantom{29)}\underline{\phantom{}87\phantom{99}}\\\phantom{29)9}60\\\phantom{29)}\underline{\phantom{9}58\phantom{9}}\\\phantom{29)99}29\\\phantom{29)}\underline{\phantom{99}29\phantom{}}\\\phantom{29)9999}0\\\end{array}$$

Since $0$ is less than $29$, stop the division. The reminder is $0$. The topmost line $0321$ is the quotient. Remove all zeros at the start of the quotient to get the actual quotient $321$.

$$\text{Quotient: }321$$ $$\text{Reminder: }0$$

Show Solution

Factor

$3\times 107$