How to solve 9430 imes428

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 9430\times428 | Equatix

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Question

$$9430 \times 428$$

Evaluate

$4036040$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}9430\\\underline{\times\phantom{9999}428}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 9430 with 8. Write the result 75440 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}9430\\\underline{\times\phantom{9999}428}\\\phantom{\times99}75440\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 9430 with 2. Write the result 18860 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}9430\\\underline{\times\phantom{9999}428}\\\phantom{\times99}75440\\\phantom{\times9}18860\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 9430 with 4. Write the result 37720 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}9430\\\underline{\times\phantom{9999}428}\\\phantom{\times99}75440\\\phantom{\times9}18860\phantom{9}\\\underline{\phantom{\times}37720\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

Show Solution

Factor

$2^{3}\times 5\times 23\times 41\times 107$