How to solve 95=9/5C+32

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 95=9/5C+32 | Equatix

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3(r+2s)=2t-4

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Question

$$95=9/5C+32$$

Solve for C

$C=35$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{9}{5}C+32=95$$

Subtract $32$ from both sides.

$$\frac{9}{5}C=95-32$$

Subtract $32$ from $95$ to get $63$.

$$\frac{9}{5}C=63$$

Multiply both sides by $\frac{5}{9}$, the reciprocal of $\frac{9}{5}$.

$$C=63\times \frac{5}{9}$$

Express $63\times \frac{5}{9}$ as a single fraction.

$$C=\frac{63\times 5}{9}$$

Multiply $63$ and $5$ to get $315$.

$$C=\frac{315}{9}$$

Divide $315$ by $9$ to get $35$.

$$C=35$$

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Question

Solve for C

Steps for Solving Linear Equation