$$[ 96 \div ( 6 ^ { 2 } - 12 ) ] \div 4 - 3 ] \times 2 + 13$$
$-2$
$$\frac{96}{\left(6^{2}-12\right)\times 4}-3$$
$$\frac{96}{\left(36-12\right)\times 4}-3$$
$$\frac{96}{24\times 4}-3$$
$$\frac{96}{96}-3$$
$$1-3$$
$$-2$$
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