Swap sides so that all variable terms are on the left hand side.
$$A^{2}=16$$
Subtract $16$ from both sides.
$$A^{2}-16=0$$
Consider $A^{2}-16$. Rewrite $A^{2}-16$ as $A^{2}-4^{2}$. The difference of squares can be factored using the rule: $a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$.
$$\left(A-4\right)\left(A+4\right)=0$$
To find equation solutions, solve $A-4=0$ and $A+4=0$.
$$A=4$$ $$A=-4$$
Steps by Finding Square Root
Divide both sides by $6$.
$$\frac{96}{6}=A^{2}$$
Divide $96$ by $6$ to get $16$.
$$16=A^{2}$$
Swap sides so that all variable terms are on the left hand side.
$$A^{2}=16$$
Take the square root of both sides of the equation.
$$A=4$$ $$A=-4$$
Steps Using the Quadratic Formula
Divide both sides by $6$.
$$\frac{96}{6}=A^{2}$$
Divide $96$ by $6$ to get $16$.
$$16=A^{2}$$
Swap sides so that all variable terms are on the left hand side.
$$A^{2}=16$$
Subtract $16$ from both sides.
$$A^{2}-16=0$$
This equation is in standard form: $ax^{2}+bx+c=0$. Substitute $1$ for $a$, $0$ for $b$, and $-16$ for $c$ in the quadratic formula, $\frac{-b±\sqrt{b^{2}-4ac}}{2a}$.
$$A=\frac{0±\sqrt{0^{2}-4\left(-16\right)}}{2}$$
Square $0$.
$$A=\frac{0±\sqrt{-4\left(-16\right)}}{2}$$
Multiply $-4$ times $-16$.
$$A=\frac{0±\sqrt{64}}{2}$$
Take the square root of $64$.
$$A=\frac{0±8}{2}$$
Now solve the equation $A=\frac{0±8}{2}$ when $±$ is plus. Divide $8$ by $2$.
$$A=4$$
Now solve the equation $A=\frac{0±8}{2}$ when $±$ is minus. Divide $-8$ by $2$.
