$$96ABC(3A-12)(5b-30) \div 144(a-4)(b-6)$$
$10ABC\left(A-4\right)\left(a-4\right)\left(b-6\right)^{2}$
$-40ABCab^{2}+480ABCab-1440ABCa+160ABCb^{2}-1920ABCb+5760ABC-1440BCA^{2}+360BCaA^{2}-120BCabA^{2}+10BCa\left(Ab\right)^{2}+480BCbA^{2}-40BC\left(Ab\right)^{2}$
