How to solve 976845 imes296

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 976845\times296 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$976845 \times 296$$

Evaluate

$289146120$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}976845\\\underline{\times\phantom{999999}296}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 976845 with 6. Write the result 5861070 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}976845\\\underline{\times\phantom{999999}296}\\\phantom{\times99}5861070\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 976845 with 9. Write the result 8791605 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}976845\\\underline{\times\phantom{999999}296}\\\phantom{\times99}5861070\\\phantom{\times9}8791605\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 976845 with 2. Write the result 1953690 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}976845\\\underline{\times\phantom{999999}296}\\\phantom{\times99}5861070\\\phantom{\times9}8791605\phantom{9}\\\underline{\phantom{\times}1953690\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

Show Solution

Factor

$2^{3}\times 3\times 5\times 37\times 65123$