How to solve 980065 389

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 980065 389 | Equatix

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Question

$$980065 \times 389$$

Evaluate

$381245285$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}980065\\\underline{\times\phantom{999999}389}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 980065 with 9. Write the result 8820585 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}980065\\\underline{\times\phantom{999999}389}\\\phantom{\times99}8820585\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 980065 with 8. Write the result 7840520 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}980065\\\underline{\times\phantom{999999}389}\\\phantom{\times99}8820585\\\phantom{\times9}7840520\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 980065 with 3. Write the result 2940195 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}980065\\\underline{\times\phantom{999999}389}\\\phantom{\times99}8820585\\\phantom{\times9}7840520\phantom{9}\\\underline{\phantom{\times}2940195\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

Show Solution

Factor

$5\times 31\times 389\times 6323$