How to solve 9895 by 472

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 9895 by 472 | Equatix

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Question

$$9895 472$$

Evaluate

$4670440$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}9895\\\underline{\times\phantom{9999}472}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 9895 with 2. Write the result 19790 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}9895\\\underline{\times\phantom{9999}472}\\\phantom{\times99}19790\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 9895 with 7. Write the result 69265 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}9895\\\underline{\times\phantom{9999}472}\\\phantom{\times99}19790\\\phantom{\times9}69265\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 9895 with 4. Write the result 39580 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}9895\\\underline{\times\phantom{9999}472}\\\phantom{\times99}19790\\\phantom{\times9}69265\phantom{9}\\\underline{\phantom{\times}39580\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

Show Solution

Factor

$2^{3}\times 5\times 59\times 1979$