Question

$$996696/ \frac{ > }{ 96 } \sqrt[ 3 ]{ 69 }$$

Answer

[No Solution]

Solution


Use this rule: \(\frac{a}{b} \times c=\frac{ac}{b}\).
\[\frac{996696}{>}\times \frac{\sqrt[3]{69}}{96}\]
Simplify  \(\times \frac{\sqrt[3]{69}}{96}\)  to  \(\frac{\sqrt[3]{69}}{96}\).
\[\frac{\frac{996696}{>\sqrt[3]{69}}}{96}\]
Since \(\frac{\frac{996696}{>\sqrt[3]{69}}}{96}\) is false, there is no solution.
No Solution