How to solve 9c ^ 4 - 36b ^ 6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 9c ^ 4 - 36b ^ 6 | Equatix

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Question

$$9c^{4}-36b^{6}$$

Factor

$9\left(c^{2}-2b^{3}\right)\left(2b^{3}+c^{2}\right)$

Solution Steps

Factor out $9$.

$$9\left(c^{4}-4b^{6}\right)$$

Consider $c^{4}-4b^{6}$. Rewrite $c^{4}-4b^{6}$ as $\left(c^{2}\right)^{2}-\left(2b^{3}\right)^{2}$. The difference of squares can be factored using the rule: $p^{2}-q^{2}=\left(p-q\right)\left(p+q\right)$.

$$\left(c^{2}-2b^{3}\right)\left(c^{2}+2b^{3}\right)$$

Reorder the terms.

$$\left(-2b^{3}+c^{2}\right)\left(2b^{3}+c^{2}\right)$$

Rewrite the complete factored expression.

$$9\left(-2b^{3}+c^{2}\right)\left(2b^{3}+c^{2}\right)$$

Show Solution

Evaluate

$9\left(c^{4}-4b^{6}\right)$