How to solve 9F=13C+225-65

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 9F=13C+225-65 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$9F=13C+225-65$$

Solve for C

$C=\frac{9F-160}{13}$

Steps for Solving Linear Equation

Subtract $65$ from $225$ to get $160$.

$$9F=13C+160$$

Swap sides so that all variable terms are on the left hand side.

$$13C+160=9F$$

Subtract $160$ from both sides.

$$13C=9F-160$$

Divide both sides by $13$.

$$\frac{13C}{13}=\frac{9F-160}{13}$$

Dividing by $13$ undoes the multiplication by $13$.

$$C=\frac{9F-160}{13}$$

Show Solution

Solve for F

$F=\frac{13C+160}{9}$

Steps for Solving Linear Equation

Subtract $65$ from $225$ to get $160$.

$$9F=13C+160$$

Divide both sides by $9$.

$$\frac{9F}{9}=\frac{13C+160}{9}$$

Dividing by $9$ undoes the multiplication by $9$.

$$F=\frac{13C+160}{9}$$

Show Solution

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Question

Solve for C

Steps for Solving Linear Equation

Solve for F

Steps for Solving Linear Equation