$$9m^{2}-\frac{1}{4}n^{2}$$
$\frac{\left(6m-n\right)\left(6m+n\right)}{4}$
$$\frac{36m^{2}-n^{2}}{4}$$
$$\left(6m-n\right)\left(6m+n\right)$$
$$\frac{\left(6m-n\right)\left(6m+n\right)}{4}$$
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$-\frac{n^{2}}{4}+9m^{2}$