How to solve 9x=(4)/(6)+20

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 9x=(4)/(6)+20 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

$$9x= \frac{ 4 }{ 6 } +20$$

$x = \frac{62}{27} = 2\frac{8}{27} \approx 2.296296296$

Reduce the fraction $\frac{4}{6}$ to lowest terms by extracting and canceling out $2$.

$$9x=\frac{2}{3}+20$$

Convert $20$ to fraction $\frac{60}{3}$.

$$9x=\frac{2}{3}+\frac{60}{3}$$

Since $\frac{2}{3}$ and $\frac{60}{3}$ have the same denominator, add them by adding their numerators.

$$9x=\frac{2+60}{3}$$

Add $2$ and $60$ to get $62$.

$$9x=\frac{62}{3}$$

Divide both sides by $9$.

$$x=\frac{\frac{62}{3}}{9}$$

Express $\frac{\frac{62}{3}}{9}$ as a single fraction.

$$x=\frac{62}{3\times 9}$$

Multiply $3$ and $9$ to get $27$.

$$x=\frac{62}{27}$$