$$9x+6y=4z2$$
$x=\frac{4z_{2}}{9}-\frac{2y}{3}$
$$9x=4z_{2}-6y$$
$$\frac{9x}{9}=\frac{4z_{2}-6y}{9}$$
$$x=\frac{4z_{2}-6y}{9}$$
$$x=\frac{4z_{2}}{9}-\frac{2y}{3}$$
Show Solution
Hide Solution
$y=\frac{2z_{2}}{3}-\frac{3x}{2}$
$$6y=4z_{2}-9x$$
$$\frac{6y}{6}=\frac{4z_{2}-9x}{6}$$
$$y=\frac{4z_{2}-9x}{6}$$
$$y=\frac{2z_{2}}{3}-\frac{3x}{2}$$