How to solve 9z+1=z+81

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 9z+1=z+81 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$9z+1=z+81$$

Solve for z

$z=10$

Steps for Solving Linear Equation

Subtract $z$ from both sides.

$$9z+1-z=81$$

Combine $9z$ and $-z$ to get $8z$.

$$8z+1=81$$

Subtract $1$ from both sides.

$$8z=81-1$$

Subtract $1$ from $81$ to get $80$.

$$8z=80$$

Divide both sides by $8$.

$$z=\frac{80}{8}$$

Divide $80$ by $8$ to get $10$.

$$z=10$$

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Question

Solve for z

Steps for Solving Linear Equation