How to solve a2+10+4-40

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve a2+10+4-40 | Equatix

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Question

$$a2+10+4-40$$

Evaluate

$a_{2}-26$

Show Solution

Differentiate w.r.t. a_2

$1$

Steps Using Derivative Rule for Sum

Add $10$ and $4$ to get $14$.

$$\frac{\mathrm{d}}{\mathrm{d}a_{2}}(a_{2}+14-40)$$

Subtract $40$ from $14$ to get $-26$.

$$\frac{\mathrm{d}}{\mathrm{d}a_{2}}(a_{2}-26)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$a_{2}^{1-1}$$

Subtract $1$ from $1$.

$$a_{2}^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$1$$

Show Solution

Example

Question

Evaluate

Solution Steps

Differentiate w.r.t. a_2

Steps Using Derivative Rule for Sum