How to solve AB+AC=A(B+C)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve AB+AC=A(B+C) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$AB+AC=A(B+C)$$

Solve for A

$A\in \mathrm{R}$

Solution Steps

Use the distributive property to multiply $A$ by $B+C$.

$$AB+AC=AB+AC$$

Subtract $AB$ from both sides.

$$AB+AC-AB=AC$$

Combine $AB$ and $-AB$ to get $0$.

$$AC=AC$$

Subtract $AC$ from both sides.

$$AC-AC=0$$

Combine $AC$ and $-AC$ to get $0$.

$$0=0$$

Compare $0$ and $0$.

$$\text{true}$$

This is true for any $A$.

$$A\in \mathrm{R}$$

Show Solution

Solve for B

$B\in \mathrm{R}$

Solution Steps

Use the distributive property to multiply $A$ by $B+C$.

$$AB+AC=AB+AC$$

Subtract $AB$ from both sides.

$$AB+AC-AB=AC$$

Combine $AB$ and $-AB$ to get $0$.

$$AC=AC$$

Reorder the terms.

$$\text{true}$$

This is true for any $B$.

$$B\in \mathrm{R}$$

Show Solution

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Example

Question

Solve for A

Solution Steps

Solve for B

Solution Steps