Solve If a = 25 then a ^ (25 ^ 0) + a ^ (0 ^ 25) = | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$a = 25 , a ^ { 25 ^ { 0 } } + a ^ { 0 ^ { 25 } } =$$

Solve for a, b

$b=26$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$b=25^{25^{0}}+25^{0^{25}}$$

Calculate $25$ to the power of $0$ and get $1$.

$$b=25^{1}+25^{0^{25}}$$

Calculate $25$ to the power of $1$ and get $25$.

$$b=25+25^{0^{25}}$$

Calculate $0$ to the power of $25$ and get $0$.

$$b=25+25^{0}$$

Calculate $25$ to the power of $0$ and get $1$.

$$b=25+1$$

Add $25$ and $1$ to get $26$.

$$b=26$$

The system is now solved.

$$a=25$$ $$b=26$$