Solve A = 15/10 - 3/24 - 21/10 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$A=\frac{15}{10}-\frac{3}{24}-\frac{21}{10}$$

Solve for A

$A=-\frac{29}{40}=-0.725$

Steps for Solving Linear Equation

Reduce the fraction $\frac{15}{10}$ to lowest terms by extracting and canceling out $5$.

$$A=\frac{3}{2}-\frac{3}{24}-\frac{21}{10}$$

Reduce the fraction $\frac{3}{24}$ to lowest terms by extracting and canceling out $3$.

$$A=\frac{3}{2}-\frac{1}{8}-\frac{21}{10}$$

Least common multiple of $2$ and $8$ is $8$. Convert $\frac{3}{2}$ and $\frac{1}{8}$ to fractions with denominator $8$.

$$A=\frac{12}{8}-\frac{1}{8}-\frac{21}{10}$$

Since $\frac{12}{8}$ and $\frac{1}{8}$ have the same denominator, subtract them by subtracting their numerators.

$$A=\frac{12-1}{8}-\frac{21}{10}$$

Subtract $1$ from $12$ to get $11$.

$$A=\frac{11}{8}-\frac{21}{10}$$

Least common multiple of $8$ and $10$ is $40$. Convert $\frac{11}{8}$ and $\frac{21}{10}$ to fractions with denominator $40$.

$$A=\frac{55}{40}-\frac{84}{40}$$

Since $\frac{55}{40}$ and $\frac{84}{40}$ have the same denominator, subtract them by subtracting their numerators.

$$A=\frac{55-84}{40}$$

Subtract $84$ from $55$ to get $-29$.

$$A=-\frac{29}{40}$$

Assign A

$A≔-\frac{29}{40}$