1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$A = \frac { 3 } { 15 } + \frac { 4 } { 15 }$$

$A=\frac{7}{15}\approx 0.466666667$

Reduce the fraction $\frac{3}{15}$ to lowest terms by extracting and canceling out $3$.

$$A=\frac{1}{5}+\frac{4}{15}$$

Least common multiple of $5$ and $15$ is $15$. Convert $\frac{1}{5}$ and $\frac{4}{15}$ to fractions with denominator $15$.

$$A=\frac{3}{15}+\frac{4}{15}$$

Since $\frac{3}{15}$ and $\frac{4}{15}$ have the same denominator, add them by adding their numerators.

$$A=\frac{3+4}{15}$$

Add $3$ and $4$ to get $7$.

$$A=\frac{7}{15}$$

$A≔\frac{7}{15}$