How to solve A=(1,1)B(2,3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve A=(1,1)B(2,3) | Equatix

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$$A=(1,1)B(2,3)$$

$B=\frac{100A}{253}$

Multiply $1,1$ and $2,3$ to get $2,53$.

$$A=2,53B$$

Swap sides so that all variable terms are on the left hand side.

$$2,53B=A$$

Divide both sides of the equation by $2,53$, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{2,53B}{2,53}=\frac{A}{2,53}$$

Dividing by $2,53$ undoes the multiplication by $2,53$.

$$B=\frac{A}{2,53}$$

Divide $A$ by $2,53$ by multiplying $A$ by the reciprocal of $2,53$.

$$B=\frac{100A}{253}$$

$A=\frac{253B}{100}$