Question

$$A \left( \begin{array} { l } { x } & { y + 4 } \\ { y + 1 } & { 2 } \\ { x + 1 } & { 2 } \end{array} \right) B = \left( \begin{array} { l } { 4 } \\ { 6 } \\ { 8 } \end{array} \right)$$

Answer

16*B

Solution


Simplify.
\[2B\times 8\]
Simplify.
\[16B\]