Question

$$A(2,-1); B(I,-1); c(\underline{\prime},3)$$

Answer

$$A*(2,-1);B*(I,-1);c*(-e^3*u*n^2*d*r^2*l*p*m,3)$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\begin{aligned}&A(2,-1)\\&B(I,-1)\\&c(u{n}^{2}d{e}^{3}{r}^{2}l{\imath }^{2}pm,3)\end{aligned}\]
Use Square Rule: \({i}^{2}=-1\).
\[\begin{aligned}&A(2,-1)\\&B(I,-1)\\&c(u{n}^{2}d{e}^{3}{r}^{2}l\times -1\times pm,3)\end{aligned}\]
Simplify  \(u{n}^{2}d{e}^{3}{r}^{2}l\times -1\times pm\)  to  \(u{n}^{2}d{e}^{3}{r}^{2}l\times -pm\).
\[\begin{aligned}&A(2,-1)\\&B(I,-1)\\&c(u{n}^{2}d{e}^{3}{r}^{2}l\times -pm,3)\end{aligned}\]
Regroup terms.
\[\begin{aligned}&A(2,-1)\\&B(I,-1)\\&c(-{e}^{3}u{n}^{2}d{r}^{2}lpm,3)\end{aligned}\]