Solve a(a - 2)(a - 4) + 4a - 8 b²(a+)(a + | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$a ( a - 2 ) ( a - 4 ) + 4 a - 8$$

Evaluate

$\left(a-2\right)^{3}$

Solution Steps

Use the distributive property to multiply $a$ by $a-2$.

$$\left(a^{2}-2a\right)\left(a-4\right)+4a-8$$

Apply the distributive property by multiplying each term of $a^{2}-2a$ by each term of $a-4$.

$$a^{3}-4a^{2}-2a^{2}+8a+4a-8$$

Combine $-4a^{2}$ and $-2a^{2}$ to get $-6a^{2}$.

$$a^{3}-6a^{2}+8a+4a-8$$

Combine $8a$ and $4a$ to get $12a$.

$$a^{3}-6a^{2}+12a-8$$

Expand

$a^{3}-6a^{2}+12a-8$

Solution Steps

Use the distributive property to multiply $a$ by $a-2$.

$$\left(a^{2}-2a\right)\left(a-4\right)+4a-8$$

Apply the distributive property by multiplying each term of $a^{2}-2a$ by each term of $a-4$.

$$a^{3}-4a^{2}-2a^{2}+8a+4a-8$$

Combine $-4a^{2}$ and $-2a^{2}$ to get $-6a^{2}$.

$$a^{3}-6a^{2}+8a+4a-8$$

Combine $8a$ and $4a$ to get $12a$.

$$a^{3}-6a^{2}+12a-8$$