Solve A(x)=(5x-2)(2x+1)+(x-2)(3x+1) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$A(x)=(5x-2)(2x+1)+(x-2)(3x+1)$$

Evaluate

$13x^{2}-4x-4$

Solution Steps

Apply the distributive property by multiplying each term of $5x-2$ by each term of $2x+1$.

$$10x^{2}+5x-4x-2+\left(x-2\right)\left(3x+1\right)$$

Combine $5x$ and $-4x$ to get $x$.

$$10x^{2}+x-2+\left(x-2\right)\left(3x+1\right)$$

Apply the distributive property by multiplying each term of $x-2$ by each term of $3x+1$.

$$10x^{2}+x-2+3x^{2}+x-6x-2$$

Combine $x$ and $-6x$ to get $-5x$.

$$10x^{2}+x-2+3x^{2}-5x-2$$

Combine $10x^{2}$ and $3x^{2}$ to get $13x^{2}$.

$$13x^{2}+x-2-5x-2$$

Combine $x$ and $-5x$ to get $-4x$.

$$13x^{2}-4x-2-2$$

Subtract $2$ from $-2$ to get $-4$.

$$13x^{2}-4x-4$$

Expand

$13x^{2}-4x-4$

Solution Steps

Apply the distributive property by multiplying each term of $5x-2$ by each term of $2x+1$.

$$10x^{2}+5x-4x-2+\left(x-2\right)\left(3x+1\right)$$

Combine $5x$ and $-4x$ to get $x$.

$$10x^{2}+x-2+\left(x-2\right)\left(3x+1\right)$$

Apply the distributive property by multiplying each term of $x-2$ by each term of $3x+1$.

$$10x^{2}+x-2+3x^{2}+x-6x-2$$

Combine $x$ and $-6x$ to get $-5x$.

$$10x^{2}+x-2+3x^{2}-5x-2$$

Combine $10x^{2}$ and $3x^{2}$ to get $13x^{2}$.

$$13x^{2}+x-2-5x-2$$

Combine $x$ and $-5x$ to get $-4x$.

$$13x^{2}-4x-2-2$$

Subtract $2$ from $-2$ to get $-4$.

$$13x^{2}-4x-4$$