Solve A+1\timesN+1-S-50=A+1.5\timesN+2-S-100 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$A+1 \times N+1-S-50=A+1.5 \times N+2-S-100$$

Solve for N

$N=98$

Steps for Solving Linear Equation

Subtract $50$ from $1$ to get $-49$.

$$A+1N-49-S=A+1.5N+2-S-100$$

Subtract $100$ from $2$ to get $-98$.

$$A+1N-49-S=A+1.5N-98-S$$

Subtract $1.5N$ from both sides.

$$A+1N-49-S-1.5N=A-98-S$$

Combine $1N$ and $-1.5N$ to get $-0.5N$.

$$A-0.5N-49-S=A-98-S$$

Subtract $A$ from both sides.

$$-0.5N-49-S=A-98-S-A$$

Combine $A$ and $-A$ to get $0$.

$$-0.5N-49-S=-98-S$$

Add $49$ to both sides.

$$-0.5N-S=-98-S+49$$

Add $-98$ and $49$ to get $-49$.

$$-0.5N-S=-49-S$$

Add $S$ to both sides.

$$-0.5N=-49-S+S$$

Combine $-S$ and $S$ to get $0$.

$$-0.5N=-49$$

Divide both sides by $-0.5$.

$$N=\frac{-49}{-0.5}$$

Expand $\frac{-49}{-0.5}$ by multiplying both numerator and the denominator by $10$.

$$N=\frac{-490}{-5}$$

Divide $-490$ by $-5$ to get $98$.

$$N=98$$

Solve for A

$A\in \mathrm{R}$
$N=98$