Solve a+2ab-(b)^(2),a=1,b=-2 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$a+2ab- { b }^{ 2 } ,a=1,b=-2$$

Solve for a, b, c

$c=-7$

Solution Steps

Consider the third equation. Insert the known values of variables into the equation.

$$c=1+2\times 1\left(-2\right)-\left(-2\right)^{2}$$

Multiply $2$ and $1$ to get $2$.

$$c=1+2\left(-2\right)-\left(-2\right)^{2}$$

Multiply $2$ and $-2$ to get $-4$.

$$c=1-4-\left(-2\right)^{2}$$

Subtract $4$ from $1$ to get $-3$.

$$c=-3-\left(-2\right)^{2}$$

Calculate $-2$ to the power of $2$ and get $4$.

$$c=-3-4$$

Subtract $4$ from $-3$ to get $-7$.

$$c=-7$$

The system is now solved.

$$a=1$$ $$b=-2$$ $$c=-7$$