$$a^{2}-\frac{6^{2}}{16}$$
$a^{2}-\frac{9}{4}$
$$a^{2}-\frac{36}{16}$$
$$a^{2}-\frac{9}{4}$$
Show Solution
Hide Solution
$\frac{\left(2a-3\right)\left(2a+3\right)}{4}$
$$\frac{4a^{2}-9}{4}$$
$$\left(2a-3\right)\left(2a+3\right)$$
$$\frac{\left(2a-3\right)\left(2a+3\right)}{4}$$
