$$a^{2}-(2b+4c)^{2}$$
$-\left(2b+4c\right)^{2}+a^{2}$
$$a^{2}-\left(4b^{2}+16bc+16c^{2}\right)$$
$$a^{2}-4b^{2}-16bc-16c^{2}$$
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$a^{2}-4b^{2}-16bc-16c^{2}$