Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$a^{3}b^{\prime\prime}+2a^{\prime}; b^{3}\frac{0}{0}a+2b$$

Answer

$$-e^2*a^3*b^p*r^2*m^2*p+2*a^prime;b^3*UNDEF*a+2*b$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\begin{aligned}&{a}^{3}{b}^{p}{r}^{2}{\imath }^{2}{m}^{2}{e}^{2}p+2{a}^{prime}\\&{b}^{3}\times \frac{0}{0}a+2b\end{aligned}\]
Use Square Rule: \({i}^{2}=-1\).
\[\begin{aligned}&{a}^{3}{b}^{p}{r}^{2}\times -1\times {m}^{2}{e}^{2}p+2{a}^{prime}\\&{b}^{3}\times \frac{0}{0}a+2b\end{aligned}\]
Simplify  \({a}^{3}{b}^{p}{r}^{2}\times -1\times {m}^{2}{e}^{2}p\)  to  \({a}^{3}{b}^{p}{r}^{2}\times -{m}^{2}{e}^{2}p\).
\[\begin{aligned}&{a}^{3}{b}^{p}{r}^{2}\times -{m}^{2}{e}^{2}p+2{a}^{prime}\\&{b}^{3}\times \frac{0}{0}a+2b\end{aligned}\]
Regroup terms.
\[\begin{aligned}&-{e}^{2}{a}^{3}{b}^{p}{r}^{2}{m}^{2}p+2{a}^{prime}\\&{b}^{3}\times \frac{0}{0}a+2b\end{aligned}\]
Simplify  \(\frac{0}{0}\)  to  \(\varnothing \).
\[\begin{aligned}&-{e}^{2}{a}^{3}{b}^{p}{r}^{2}{m}^{2}p+2{a}^{prime}\\&{b}^{3}\varnothing a+2b\end{aligned}\]
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