$$a^{3}+b^{2}; b^{2}-2ab$$
$b\left(b-2a\right)\left(a^{3}+b^{2}\right)$
$$b\left(b-2a\right)\left(a^{3}+b^{2}\right)$$
$$-2ab^{3}+b^{4}+b^{2}a^{3}-2ba^{4}$$
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$a^{3}+b^{2},\ b\left(b-2a\right)$
