$$a_{n}=1.2-3n$$
$n=-\frac{a_{n}}{3}+0.4$
$$1.2-3n=a_{n}$$
$$-3n=a_{n}-1.2$$
$$\frac{-3n}{-3}=\frac{a_{n}-1.2}{-3}$$
$$n=\frac{a_{n}-1.2}{-3}$$
$$n=-\frac{a_{n}}{3}+\frac{2}{5}$$
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$a_{n}=1.2-3n$
