$$a_{n}=12n-1$$
$n=\frac{a_{n}+1}{12}$
$$12n-1=a_{n}$$
$$12n=a_{n}+1$$
$$\frac{12n}{12}=\frac{a_{n}+1}{12}$$
$$n=\frac{a_{n}+1}{12}$$
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$a_{n}=12n-1$
