$$a _ { n } = 4 n + 12$$
$n=\frac{a_{n}-12}{4}$
$$4n+12=a_{n}$$
$$4n=a_{n}-12$$
$$\frac{4n}{4}=\frac{a_{n}-12}{4}$$
$$n=\frac{a_{n}-12}{4}$$
$$n=\frac{a_{n}}{4}-3$$
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$a_{n}=4\left(n+3\right)$
