Question

$$a_{n=}(n+1)a_{n-1},a_{1}=1.$$

Answer

$$a=1/n^2,0$$

Solution


Regroup terms.
\[\begin{aligned}&an=an(n+1)-1\\&a\times 1=1.\end{aligned}\]
Simplify  \(a\times 1\)  to  \(a\).
\[\begin{aligned}&an=an(n+1)-1\\&a=1.\end{aligned}\]
Break down the problem into these 2 equations.
\[an=an(n+1)-1\]
\[an=a\]
Solve the 1st equation: \(an=an(n+1)-1\).
\[a=\frac{1}{{n}^{2}}\]
Solve the 2nd equation: \(an=a\).
\[a=0\]
Collect all solutions.
\[a=\frac{1}{{n}^{2}},0\]