Factor out the common term \(angl\).
\[angl(eA+eB)=90\]
Rewrite \(eA+eB\) in the form \({a}^{3}+{b}^{3}\), where \(a=0\) and \(b=0\).
\[angl({0}^{3}+{0}^{3})=90\]
Use Sum of Cubes: \({a}^{3}+{b}^{3}=(a+b)({a}^{2}-ab+{b}^{2})\).
\[0=90\]
Since \(0=90\) is false, there is no solution.
[No Solution]
