Question

$$ax+b=x$$

Solve for a (complex solution)

$\left\{\begin{matrix}a=\frac{x-b}{x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&x=0\text{ and }b=0\end{matrix}\right.$

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Solve for a

$\left\{\begin{matrix}a=\frac{x-b}{x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&x=0\text{ and }b=0\end{matrix}\right.$

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Solve for b

$b=x\left(1-a\right)$

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