Solve aligned 23 1\\ *3 0 5 aligned | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\begin{aligned}23\ 1&\\ \times3\ 0\ 5&\end{aligned}$$

Evaluate

$70455$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}231\\\underline{\times\phantom{99}305}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 231 with 5. Write the result 1155 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}231\\\underline{\times\phantom{99}305}\\\phantom{\times9}1155\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 231 with 0. Write the result 0 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}231\\\underline{\times\phantom{99}305}\\\phantom{\times9}1155\\\phantom{\times9999}0\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 231 with 3. Write the result 693 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}231\\\underline{\times\phantom{99}305}\\\phantom{\times9}1155\\\phantom{\times9999}0\phantom{9}\\\underline{\phantom{\times}693\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}231\\\underline{\times\phantom{99}305}\\\phantom{\times9}1155\\\phantom{\times9999}0\phantom{9}\\\underline{\phantom{\times}693\phantom{99}}\\\phantom{\times}70455\end{array}$$

Factor

$3\times 5\times 7\times 11\times 61$