Solve for \(y\) in \(2e+y=25\).
Solve for \(y\).
\[2e+y=25\]
Subtract \(2e\) from both sides.
\[y=25-2e\]
\[y=25-2e\]
Substitute \(y=25-2e\) into \(2ey=150\).
Start with the original equation.
\[2ey=150\]
Let \(y=25-2e\).
\[2e(25-2e)=150\]
\[2e(25-2e)=150\]
Since \(2e(25-2e)=150\) is not true, this is an inconsistent system.
