Solve for \(x\) in \(2y=5x+6\).
Solve for \(x\).
\[2y=5x+6\]
Subtract \(6\) from both sides.
\[2y-6=5x\]
Divide both sides by \(5\).
\[\frac{2y-6}{5}=x\]
Factor out the common term \(2\).
\[\frac{2(y-3)}{5}=x\]
Switch sides.
\[x=\frac{2(y-3)}{5}\]
\[x=\frac{2(y-3)}{5}\]
Substitute \(x=\frac{2(y-3)}{5}\) into \(-10x+4y=8\).
Start with the original equation.
\[-10x+4y=8\]
Let \(x=\frac{2(y-3)}{5}\).
\[-10\times \frac{2(y-3)}{5}+4y=8\]
Simplify.
\[12=8\]
\[12=8\]
Since \(12=8\) is not true, this is an inconsistent system.
