Solve for \(y\) in \(2x-y=-12\).
Solve for \(y\).
\[2x-y=-12\]
Subtract \(2x\) from both sides.
\[-y=-12-2x\]
Multiply both sides by \(-1\).
\[y=12+2x\]
\[y=12+2x\]
Substitute \(y=12+2x\) into \(-4x+2y=3\).
Start with the original equation.
\[-4x+2y=3\]
Let \(y=12+2x\).
\[-4x+2(12+2x)=3\]
Simplify.
\[24=3\]
\[24=3\]
Since \(24=3\) is not true, this is an inconsistent system.
