Substitute \(x=3y-2\) into \(4x+3y=-3\).
Start with the original equation.
\[4x+3y=-3\]
Let \(x=3y-2\).
\[4(3y-2)+3y=-3\]
Simplify.
\[15y-8=-3\]
\[15y-8=-3\]
Solve for \(y\) in \(15y-8=-3\).
Solve for \(y\).
\[15y-8=-3\]
Add \(8\) to both sides.
\[15y=-3+8\]
Simplify \(-3+8\) to \(5\).
\[15y=5\]
Divide both sides by \(15\).
\[y=\frac{5}{15}\]
Simplify \(\frac{5}{15}\) to \(\frac{1}{3}\).
\[y=\frac{1}{3}\]
\[y=\frac{1}{3}\]
Substitute \(y=\frac{1}{3}\) into \(x=3y-2\).
Start with the original equation.
\[x=3y-2\]
Let \(y=\frac{1}{3}\).
\[x=3\times \frac{1}{3}-2\]
Simplify.
\[x=-1\]
\[x=-1\]
Therefore,
\[\begin{aligned}&x=-1\\&y=\frac{1}{3}\end{aligned}\]
x=-1;y=1/3
