Solve for \(x\) in \(x-y=4\).
Solve for \(x\).
\[x-y=4\]
Add \(y\) to both sides.
\[x=4+y\]
\[x=4+y\]
Substitute \(x=4+y\) into \(-2x+2y=1\).
Start with the original equation.
\[-2x+2y=1\]
Let \(x=4+y\).
\[-2(4+y)+2y=1\]
Simplify.
\[-8=1\]
\[-8=1\]
Since \(-8=1\) is not true, this is an inconsistent system.
