Question

$$[\begin{matrix}3&4\\ -1&-2\end{matrix}][\begin{matrix}-1\\ 2\end{matrix}]; 3x-1+4\times2$$

Answer

[[3,4],[-1,-2]]*[[-1],[2]];3*x-1+8

Solution


Simplify  \(4\times 2\)  to  \(8\).
\(\(3,4\\)]*\(\(-1\\)];3*x-1+8