Question

$$B\cap B^{c}=\phi$$

Answer

$$a=(p*h*IM)/(Bc*pB^c)$$

Solution


Divide both sides by \(Bc\).
\[a{pB}^{c}=\frac{ph\imath }{Bc}\]
Divide both sides by \({pB}^{c}\).
\[a=\frac{\frac{ph\imath }{Bc}}{{pB}^{c}}\]
Simplify  \(\frac{\frac{ph\imath }{Bc}}{{pB}^{c}}\)  to  \(\frac{ph\imath }{Bc{pB}^{c}}\).
\[a=\frac{ph\imath }{Bc{pB}^{c}}\]