How to solve B=|4- 1 4 :7|=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve B=|4- 1 4 :7|= | Equatix

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$$B=|4-\frac{1}{4}:7|=$$

$B = \frac{111}{28} = 3\frac{27}{28} \approx 3.964285714$

Express $\frac{\frac{1}{4}}{7}$ as a single fraction.

$$B=|4-\frac{1}{4\times 7}|$$

Multiply $4$ and $7$ to get $28$.

$$B=|4-\frac{1}{28}|$$

Convert $4$ to fraction $\frac{112}{28}$.

$$B=|\frac{112}{28}-\frac{1}{28}|$$

Since $\frac{112}{28}$ and $\frac{1}{28}$ have the same denominator, subtract them by subtracting their numerators.

$$B=|\frac{112-1}{28}|$$

Subtract $1$ from $112$ to get $111$.

$$B=|\frac{111}{28}|$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $\frac{111}{28}$ is $\frac{111}{28}$.

$$B=\frac{111}{28}$$

$B≔\frac{111}{28}$