Question

$$\beta=90^{\circ}-68^{\circ}$$

Answer

$$b=-(6120*de*g^2*d)/(t*a)$$

Solution


Remove parentheses.
\[beta=90deg\times -68deg\]
Cancel \(e\) on both sides.
\[bta=90deg\times -68dg\]
Take out the constants.
\[bta=(90\times -68)ggdde\]
Simplify  \(90\times -68\)  to  \(-6120\).
\[bta=-6120ggdde\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[bta=-6120{g}^{2}dde\]
Regroup terms.
\[bta=-6120de{g}^{2}d\]
Divide both sides by \(t\).
\[ba=-\frac{6120de{g}^{2}d}{t}\]
Divide both sides by \(a\).
\[b=-\frac{\frac{6120de{g}^{2}d}{t}}{a}\]
Simplify  \(\frac{\frac{6120de{g}^{2}d}{t}}{a}\)  to  \(\frac{6120de{g}^{2}d}{ta}\).
\[b=-\frac{6120de{g}^{2}d}{ta}\]