1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$B = \frac { \frac { 4 } { 5 } } { \frac { 2 } { 3 } } \frac { - 3 } { 3 }$$

$B = -\frac{6}{5} = -1\frac{1}{5} = -1.2$

Divide $\frac{4}{5}$ by $\frac{2}{3}$ by multiplying $\frac{4}{5}$ by the reciprocal of $\frac{2}{3}$.

$$B=\frac{4}{5}\times \frac{3}{2}\times \frac{-3}{3}$$

Multiply $\frac{4}{5}$ times $\frac{3}{2}$ by multiplying numerator times numerator and denominator times denominator.

$$B=\frac{4\times 3}{5\times 2}\times \frac{-3}{3}$$

Do the multiplications in the fraction $\frac{4\times 3}{5\times 2}$.

$$B=\frac{12}{10}\times \frac{-3}{3}$$

Reduce the fraction $\frac{12}{10}$ to lowest terms by extracting and canceling out $2$.

$$B=\frac{6}{5}\times \frac{-3}{3}$$

Divide $-3$ by $3$ to get $-1$.

$$B=\frac{6}{5}\left(-1\right)$$

Multiply $\frac{6}{5}$ and $-1$ to get $-\frac{6}{5}$.

$$B=-\frac{6}{5}$$

$B≔-\frac{6}{5}$